Let the radius of the larger circle be $R$ and the radius of smaller circle be $r$.
Given $r=14.$
$2\pi R - 2\pi r = 132$
$2\pi\left(R-r \right)=132$
$\pi\left(R-r \right)=66$
Consider $\pi = \frac{22}{7}$.
$R-14 = \frac{66\times7}{22}=21$
$R=21+14=35cms$.
Hence Option E is the correct answer.