Conical cavity is drilled in a circular cylinder of height 15 cm and base radius 8 cm. The height and base of the radius of the cone are also same. Find the whole surface area of remaining solid?

Conical cavity is drilled in a circular cylinder of height 15 cm and base radius 8 cm. The height and base of the radius of the cone are also same. Find the whole surface area of remaining solid?
1). 440π cm²
2). 240π cm²
3). 640π cm²
4). 960π cm²

⇒ l = $(\sqrt {{r^2} + \;{h^2}} \; = \;\sqrt {{{15}^2} + \;{8^2}} \; = \;17\;cm)$

here, l = slant height of cylinder

r = radius of cylinder

h = height of cylinder

⇒ Total remaining surface area = $(2\pi rh + \;\pi {r^2} + \;\pi rl)$

⇒ 2π × 8 × 15 + π × 64 + π × 136

⇒ 440π cm²

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