X and Y are two alloys which are prepared by mixing zinc and aluminium in the ratio of 1 : 4 and 11 : 8 respectively. If equal quantities of alloys are melted to form a third alloy Z then what is the ratio of zinc and aluminium in alloy Z?

X and Y are two alloys which are prepared by mixing zinc and aluminium in the ratio of 1 : 4 and 11 : 8 respectively. If equal quantities of alloys are melted to form a third alloy Z then what is the ratio of zinc and aluminium in alloy Z?
1). 32 : 47
2). 37 : 58
3). 37 : 95
4). 74 : 95

Ratio of zinc and aluminium in alloy X = 1 : 4 = 5 unit

Ratio of zinc and aluminium in alloy Y = 11 : 8 = 19 unit

We have to equal quantities

Ratio of zinc and aluminium in alloy X = 1 : 4 = 5 × 19

Ratio of zinc and aluminium in alloy Y = 11 : 8 = 19 × 5

New ratio of zinc and aluminium in alloy X = 19 : 76 = 95 unit

New ratio of zinc and aluminium in alloy Y = 55 : 40 = 95 unit

∴ Ratio of zinc and aluminium in alloy Z = (19 + 55) : (76 + 40) = 74 : 116 = 37 : 58

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