Direction: Read the information carefully and answer the questions that follow:
In a certain code language, the symbol for ’0’ is ‘@’ and ‘1’ is ‘#’. There are no other symbols for numbers greater than one. The numbers greater than one are to be written only by using the two symbols given above.
0 is written as @,
1 is written as #,
2 is written as #@,
3 is written as ##,
4 is written as #@@ and so on.##@@@# = 110001
= (1 x 2?) + (1 x 2?) + (0 x 2³) + (0 x 2²) + (0 x 2¹) + (1 x 20)
= 32 + 16 + 0 + 0 + 0 + 1
= 49
##@@## = 110011
= ((1 x 2?) + (1 x 2?) + (0 x 2³) + (0 x 2²) + (1 x 2¹) + (1 x 20$)
= 32 + 16 + 0 + 0+ 2 + 1
= 51
#@@@#@ = 100010
= (1 x 2?) + (0 x 2?) + (0 x 2³) + (0 x 2²) + (1 x 2¹) + (0 x 20$)
= 32 + 0 + 0 + 0 + 2 + 0
= 34
@@@##@ = 000110
= (0 x 2?) + (0 x 2?) + (0 x 2³) + (1 x 2²) + (1 x 2¹) + (1 x 20)
= 0 + 0 + 0 + 4 + 2 + 0
= 6
@##@@# = 011001
= (0 x 2?) + (1 x 2?) + (1 x 2³) + (0 x 2²) + (0 x 2¹) + (1 x 20)
= 0 + 16 + 8 + 0 + 0 + 1
= 25
So, #@@@#@ is the option which represents the value 34.