An alloy has Iron, Silver and Bronze in the ratio 7 : 2 : 3. Another alloy has Silver and Bronze in ratio 1 : 2. In what ratio should the two mixtures be mixed so that the ratio of Iron and Silver in resultant mixture is 5 : 3?

Suppose M kg of first alloy and N kg of second alloy is taken.

Amount of Iron in first alloy = 7M/12 kg

Amount of Silver in first alloy = 2M/12 kg

Amount of Silver in second alloy = N/3 kg

Ratio of Iron and Silver in mixture is 5 : 3.

(7M/12)/(2M/12 + N/3) = 5/3

(7M/(2M + 4N)) = 5/3

21M = 10M + 20N

11M = 20N

M/N = 20/11

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