The volume of the plaster $= 100 m2 × 0.015 m = 1.5 m^3$
We have to increase the mortar value by (To accommodate new wall depression & wastages volume of plaster)
Increase mortar for uniform wall by $30-35%$
For volume of dry mortar increase $25%$
So, it is possible to go around $60%$ extra volume for dry & wet mortar.
Therefore, volume of dry mortar = $(1.5 \times \frac{{160}}{{100}} = 2.4)$
Now $1$ part is of cement has $6$ part is of sand so,
Cement $= (1/7) × 2.4 = 0.343 m^3$