Given that, voltage (V) = 100 V
Frequency (f) = 10 kHz
Current (I) = 10 mA
$({X_L} = \frac{V}{I} = \frac{{100}}{{10 \times {{10}^{ - 3}}}} = {10^4}{\\rm{\;\Omega }})$
$(\Rightarrow 2\pi fL = {10^4})$
$(\Rightarrow L = \frac{{{{10}^4}}}{{2\pi \times 10 \times {{10}^3}}} = 159.15\;mH \approx 160\;mH)$