After working for 6 days, Ashok finds that only 1/3 rd of the work has been done. He employs Ravi who is 60% as efficient as Ashok. How many days more would Ravi take to complete the work?

 After working for 6 days, Ashok finds that only 1/3 rd of the work has been done. He employs Ravi who is 60% as efficient as Ashok. How many days more would Ravi take to complete the work?

A). 19 days

B). 10 days

C). 20 days

D). 12 days

Let Ashok's work rate be $A$ (i.e., the fraction of work he completes per day).

Since Ashok completes $\frac{1}{3}$ of the work in **6 days**, his daily work rate is:
$A = \frac{1}{3} \div 6 = \frac{1}{18}$
Thus, Ashok alone can complete the entire work in **18 days**.

Now, the remaining work to be done is:
$1 - \frac{1}{3} = \frac{2}{3}$

Ravi's efficiency is **60% of Ashok's**, so his work rate is:
$R = 0.6 \times A = 0.6 \times \frac{1}{18} = \frac{1}{30}$

Now, let **x** be the number of days Ravi takes to complete the remaining $\frac{2}{3}$ of the work:
$x \times \frac{1}{30} = \frac{2}{3}$

Solving for **x**:
$x = \frac{2}{3} \times 30 = 20$

Thus, the correct answer is:

$\boxed{20}$ **days**

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