The sum of two numbers is 36 and their H.C.F. is 4. How many pairs of such numbers are possible

HCF of two numbers = 4.

Hence, the numbers can be given by 4x and 4y where x and y are co-prime.

Then, 4x + 4y = 36

4 (x + y) = 36

x + y = 9

Possible pairs satisfying this condition are : (1, 8), (4, 5), (2, 7)

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