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Find (61 + 62 + 63 + ……… + 110) = ?
Find (61 + 62 + 63 + ……… + 110) = ?
1). 4275
2). 8550
3). 12825
4). 17100
1). 4275
2). 8550
3). 12825
4). 17100
This Question has 1 answers.
This sequence forms an A.P with common difference 1
Therefore, an = a + (n - 1)d
Where, an = nth term
a = first term
n = number of terms
d = common difference
Applying the formula, we get,
110 = 61 + (n - 1)
n = 50
Therefore, Sn = n (a + l)/2
Where, Sn = sum of nth terms
n = number of terms
a = first term
l = last term
Now, applying the formula and obtain the sum
S = 50(61 + 110)/2
S = (50 × 171)/2
S = 4275Similar Questions
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