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Find (61 + 62 + 63 + ……… + 110) = ?

Find (61 + 62 + 63 + ……… + 110) = ?
1). 4275
2). 8550
3). 12825
4). 17100

This Question has 1 answers.

This sequence forms an A.P with common difference 1

Therefore, an = a + (n - 1)d

Where, an = nth term

a = first term

n = number of terms

d = common difference

Applying the formula, we get,

110 = 61 + (n - 1)

n = 50

Therefore, Sn = n (a + l)/2

Where, Sn = sum of nth terms

n = number of terms

a = first term

l = last term

Now, applying the formula and obtain the sum

S = 50(61 + 110)/2

S = (50 × 171)/2

S = 4275

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