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The average of 41 consecutive odd numbers is 49. What is the largest number?
The average of 41 consecutive odd numbers is 49. What is the largest number?
1). 89
2). 91
3). 93
4). 95
1). 89
2). 91
3). 93
4). 95
This Question has 2 answers.
Since given that average of $41$ consecutive odd numbers is $49$,
Which implies that middle number is $49$ and there are $20$ numbers greater than that,
The largest number $= 49 + 20 × 2 = 89$
The largest number is $89$.49+(41-1)=89
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