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A liquid 'P' is $1\frac{3}{7}$ times as heavy as water and water is $1\frac{2}{5}$ times as heavy as another liquid 'Q' The amount of liquid ‘P' that must be added to 7 litres of the liquid ‘Q' so that the mixture may weigh as much as an equal volume of w
A liquid 'P' is $1\frac{3}{7}$ times as heavy as water and water is $1\frac{2}{5}$ times as heavy as another liquid 'Q' The amount of liquid ‘P' that must be added to 7 litres of the liquid ‘Q' so that the mixture may weigh as much as an equal volume of water ,will be
1). 7 litres
2). $5\frac{1}{6}$ litres
3). 5 litres
4). $4\frac{2}{3}$ litres
1). 7 litres
2). $5\frac{1}{6}$ litres
3). 5 litres
4). $4\frac{2}{3}$ litres
This Question has 3 answers.
option 4 is the right one
Let $x$ litres of liquid P be mixed to $7$ litres of liquid Q.
According to the question,
$x\times\frac{10}{7}$+$\frac{5}{7}\times7$ = x+7
$10x + 35 = 7x + 49$
$= 10x – 7x = 49 – 35$
$= 3x = 14$
$x = 4 \frac{2}{3}$
USING ALLIGATION
P: W= 10:7
W:Q = 7:5
P:W:Q = 10:7:5
We have make P and Q equal to water
So,
P Q
10. 5
7
7-5. 10-7
2. 3
Now, 3 units = 7
So 1 unit = 7/3 and
2 units = 7/3 *2 = 14/3
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