A liquid 'P' is $1\frac{3}{7}$ times as heavy as water and water is $1\frac{2}{5}$ times as heavy as another liquid 'Q' The amount of liquid ‘P' that must be added to 7 litres of the liquid ‘Q' so that the mixture may weigh as much as an equal volume of w

Let $x$ litres of liquid P be mixed to $7$ litres of liquid Q.
According to the question,

$x\times\frac{10}{7}$+$\frac{5}{7}\times7$ = x+7

$10x + 35 = 7x + 49$
$= 10x – 7x = 49 – 35$
$= 3x = 14$

$x = 4 \frac{2}{3}$

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