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In triangle PQR, A is the point of intersection of all the altitudes and B is the point of intersection of all the angle bisectors of the triangle. If $\angle PBR$ =$105^{0}$, then what is the value of $\angle PAR$ (in degrees)?
In triangle PQR, A is the point of intersection of all the altitudes and B is the point of intersection of all the angle bisectors of the triangle. If $\angle PBR$ =$105^{0}$, then what is the value of $\angle PAR$ (in degrees)?
1). 60
2). 100
3). 105
4). 115
1). 60
2). 100
3). 105
4). 115
This Question has 2 answers.
is 60 is the correct answer?? am i right?
150 degrees is the correct answer.
60 degrees is answer for circumcentre( point of intersection of perpendicular bisectors )
not for orthocentre ( point of intersection of altitudes).
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