In $\triangle ABC, \angle B= 90°$. if $\frac{AB}{AC} = \frac{1}{2}$, then $cos$ $C$ is equal to
In $\triangle ABC, \angle B= 90°$. if $\frac{AB}{AC} = \frac{1}{2}$, then $cos$ $C$ is equal to
a) 3/2
b) 1/2
c) $\frac{\sqrt{3}}{2}$
d) $\frac{1}{\sqrt{3}}$
This Question has
1
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Answer #1859
In $\triangle ABC$, given that $\angle B = 90^\circ$, and
$ \displaystyle \frac{AB}{AC} = \frac{1}{2} $,
we need to find $\cos C$.
### Step 1: Define Trigonometric Ratio
By definition,
$ \displaystyle \cos C = \frac{\text{adjacent side}}{\text{hypotenuse}} = \frac{AB}{AC} $
### Step 2: Substitute Given Values
Since we are given
$ \displaystyle \frac{AB}{AC} = \frac{1}{2} $,
it follows that:
$ \displaystyle \cos C = \frac{1}{2} $.
### Final Answer:
$ \cos C = \frac{1}{2} $.
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