The sum of two positive numbers is 20% of the sum of their squares and 25% of the difference of their squares. If the numbers are x and y then,$\frac{x+y}{x^{2}}$ is equal to

option 4 is the correct answer 

. According to question

$\frac{x+y}{x^{2}}$ = $\frac{x^{2}+y^{2}}{5x^{2}}$

= $\frac{9y^{2}+y^{2}}{5\times9y^{2}}$ = $\frac{10y^{2}}{45y^{2}}$ = $\frac{2}{9}$

Acc to question

x+y =1(x^2+y^2)/5

x+y= 1(x^2-y^2)/4

1(x^2+y^2)/5= 1(x^2-y^2)/4

4x^2+4y^2= 5x^2-5y^2

9y^2 = x^2

x+y/x^2 = (x^2+ y^2)/5x^2

x+ylx^2= 9y^2+y^2/5*9y^2

=10y^2/45y^2

=10/45= 2/9

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