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In an AC circuit, V and I are given by: V = 100 sin (100t) volts and I = 100 sin (100t + π/3) mA. The power dissipated in the circuit is
In an AC circuit, V and I are given by: V = 100 sin (100t) volts and I = 100 sin (100t + π/3) mA. The power dissipated in the circuit is
1). 2.5 W
2). 10 W
3). 2500 W
4). 10000 W
1). 2.5 W
2). 10 W
3). 2500 W
4). 10000 W
This Question has 1 answers.
V = 100 sin (100t) volts and
I = 100 sin (100t + π/3) mA
Phase difference = π/3
Power dissipated, $(P = {V_{rms}}{I_{rms}}\cos \phi)$
$(= \frac{{100}}{{\sqrt 2 }} \\times \frac{{0.1}}{{\sqrt 2 }} \times \cos \frac{\pi }{3} = 2.5\;W)$Similar Questions
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