In an alloy, zinc and copper are in the ratio 1 : 2. In the second alloy, the same elements are in the ratio 2 : 3. If these two alloys be mixed to form a new alloy in which two elements are in the ratio 5:8, the ratio of these two alloys in the new allow

Required ratio = 3 :10

In 1st alloy $1 : 2 =3$

In 2nd alloy. $2 : 3 =5$

In 3rd alloy. $5 : 8 = 13$

LCM of $3, 5 ,13$ is $195$

In 1st alloy$ 65:130$

Since $3\times65=195 $

So the wt of 1st alloy is$ 65$

therefore $1 \times 65 : 2 \times 65 = 65 : 130$

Similarly, in 2nd alloy, $78:117$

Since$ 5 \times 39=195$

So the wt of 2nd alloy is$ 39.$

Therefore$ 2 \times 39 : 3 \times 39= 78 : 117$

In 3rd alloy, $75:120$

By alligation method,$ 78-75=3 75-65=10$

Therefore the ratio is $3:10$

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