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After working for 6 days, Ashok finds that only 1/3 rd of the work has been done. He employs Ravi who is 60% as efficient as Ashok. How many days more would Ravi take to complete the work?
After working for 6 days, Ashok finds that only 1/3 rd of the work has been done. He employs Ravi who is 60% as efficient as Ashok. How many days more would Ravi take to complete the work?
A). 19 days
B). 10 days
C). 20 days
D). 12 days
This Question has 1 answers.
Let Ashok's work rate be $A$ (i.e., the fraction of work he completes per day).
Since Ashok completes $\frac{1}{3}$ of the work in **6 days**, his daily work rate is:
$A = \frac{1}{3} \div 6 = \frac{1}{18}$
Thus, Ashok alone can complete the entire work in **18 days**.
Now, the remaining work to be done is:
$1 - \frac{1}{3} = \frac{2}{3}$
Ravi's efficiency is **60% of Ashok's**, so his work rate is:
$R = 0.6 \times A = 0.6 \times \frac{1}{18} = \frac{1}{30}$
Now, let **x** be the number of days Ravi takes to complete the remaining $\frac{2}{3}$ of the work:
$x \times \frac{1}{30} = \frac{2}{3}$
Solving for **x**:
$x = \frac{2}{3} \times 30 = 20$
Thus, the correct answer is:
$\boxed{20}$ **days**
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