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The line $2x - 3y = 6$ intersects $x - axis$ at
The line $2x - 3y = 6$ intersects $x - axis$ at:
(A) (0, - 2)
(B) (0, 3)
(C) (- 2, 0)
(D) (3, 0)
This Question has 1 answers.
To find the x-intercept of the line $ \displaystyle 2x - 3y = 6 $, we set $ \displaystyle y = 0 $ and solve for $ \displaystyle x $.
Substituting $ \displaystyle y = 0 $ into the equation:
$ \displaystyle 2x - 3(0) = 6 $
$ \displaystyle 2x = 6 $
$ \displaystyle x = 3 $
Thus, the line intersects the x-axis at $ \displaystyle (3,0) $.
Substituting $ \displaystyle y = 0 $ into the equation:
$ \displaystyle 2x - 3(0) = 6 $
$ \displaystyle 2x = 6 $
$ \displaystyle x = 3 $
Thus, the line intersects the x-axis at $ \displaystyle (3,0) $.
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