Three coins are tossed together. The probability that exactly one coin shows head, is

Three coins are tossed together. The probability that exactly one coin shows head, is

When three coins are tossed together, the total number of possible outcomes is:

$ \displaystyle 2^3 = 8 $

The sample space is:

HHH, HHT, HTH, HTT, THH, THT, TTH, TTT

We need to find the probability of getting exactly one head. The favorable outcomes are:

$ \{HTT, THT, TTH\} $

There are $3$ such outcomes.

Thus, the required probability is:

$ \displaystyle P(\text{exactly one head}) = \frac{3}{8} $

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