If $\sqrt{3} sin \theta = cos \theta$ , then value of $\theta$ is:

If $\sqrt{3} sin \theta = cos \theta$ , then value of $\theta$ is:

We are given the equation:

$ \displaystyle \sqrt{3} \sin \theta = \cos \theta $

### Step 1: Express in Terms of $\tan \theta$
Dividing both sides by $\cos \theta$:

$ \displaystyle \frac{\sqrt{3} \sin \theta}{\cos \theta} = \frac{\cos \theta}{\cos \theta} $

$ \displaystyle \sqrt{3} \tan \theta = 1 $

$ \displaystyle \tan \theta = \frac{1}{\sqrt{3}} $

### Step 2: Solve for $\theta$
We know that:

$ \displaystyle \tan 30^\circ = \frac{1}{\sqrt{3}} $

Thus,

$ \displaystyle \theta = 30^\circ $

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