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A vessel contains 20 litres of acid. 4 litres of acid is taken out of the vessel and replaced by the same quantity of water. Next 4 litres of the mixture are with, drawn, and again the vessel is filled with the same quantity add left in the vessel with t
A vessel contains 20 litres of acid. 4 litres of acid is taken out of the vessel and replaced by the same quantity of water. Next 4 litres of the mixture are with, drawn, and again the vessel is filled with the same quantity add left in the vessel with the quantity of acid initially in the vessel is
1). 4:5
2). 4:25
3). 16:25
4). 1:5
1). 4:5
2). 4:25
3). 16:25
4). 1:5
This Question has 3 answers.
option 3 is the right answer
Remaining acid
= Initial quantity = 20$(1-\frac{4}{20})^{2}$ = 12. 8 litres
Required ratio = 12.8 : 20
= 128 : 200
= 16 : 25
Initial quantity = 20 (1- 4/20)2
= 12.8 liter
Required ratio = 12.8 : 20
128 : 200
= 16 : 25
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