A vessel contains 20 litres of acid. 4 litres of acid is taken out of the vessel and replaced by the same quantity of water. Next 4 litres of the mixture are with, drawn, and again the vessel is filled with the same quantity add left in the vessel with t

Remaining acid
= Initial quantity = 20$(1-\frac{4}{20})^{2}$ = 12. 8 litres
Required ratio = 12.8 : 20
= 128 : 200

= 16 : 25

Initial quantity = 20 (1- 4/20)²

^{= 12.8 liter} 

^{Required ratio = 12.8 : 20}

^{128 : 200}

^{= 16 : 25}

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